4y^2+2=4(y+y)+2

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Solution for 4y^2+2=4(y+y)+2 equation:


Simplifying
4y2 + 2 = 4(y + y) + 2

Reorder the terms:
2 + 4y2 = 4(y + y) + 2

Combine like terms: y + y = 2y
2 + 4y2 = 4(2y) + 2

Remove parenthesis around (2y)
2 + 4y2 = 4 * 2y + 2

Multiply 4 * 2
2 + 4y2 = 8y + 2

Reorder the terms:
2 + 4y2 = 2 + 8y

Add '-2' to each side of the equation.
2 + -2 + 4y2 = 2 + -2 + 8y

Combine like terms: 2 + -2 = 0
0 + 4y2 = 2 + -2 + 8y
4y2 = 2 + -2 + 8y

Combine like terms: 2 + -2 = 0
4y2 = 0 + 8y
4y2 = 8y

Solving
4y2 = 8y

Solving for variable 'y'.

Reorder the terms:
-8y + 4y2 = 8y + -8y

Combine like terms: 8y + -8y = 0
-8y + 4y2 = 0

Factor out the Greatest Common Factor (GCF), '4y'.
4y(-2 + y) = 0

Ignore the factor 4.

Subproblem 1

Set the factor 'y' equal to zero and attempt to solve: Simplifying y = 0 Solving y = 0 Move all terms containing y to the left, all other terms to the right. Simplifying y = 0

Subproblem 2

Set the factor '(-2 + y)' equal to zero and attempt to solve: Simplifying -2 + y = 0 Solving -2 + y = 0 Move all terms containing y to the left, all other terms to the right. Add '2' to each side of the equation. -2 + 2 + y = 0 + 2 Combine like terms: -2 + 2 = 0 0 + y = 0 + 2 y = 0 + 2 Combine like terms: 0 + 2 = 2 y = 2 Simplifying y = 2

Solution

y = {0, 2}

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